0.5 L bottle 4 g sugar 30 min covert 50% rate

0.5 L bottle 4 g sugar 30 min covert 50% rate

A reaction of great social significance is the fermentation of sugar with yeast. This is a zero-order (in sugar) reaction, where the yeast is a catalyst (it does not enter the reaction itself). If a 0.5 L bottle contains 4 g of sugar, and it takes 30 min to convert 50% of the sugar, what is the rate constant?

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[A]_t = –kt + [A]_0

( 참고 https://ywpop.tistory.com/6434 )

(4 g / 0.5 L) × 0.5 = –k × 30 min + (4 g / 0.5 L)

4 = –30k + 8

30k = 4

k = 4 / 30

= 0.133 g/L•min

답: 0.133 g/L•min

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