반-당량점 pH. 1.250 M CH3CH2NH2 151 mL + 0.520 M HCl

Calculate the pH at the half-way point of the titration of

151 mL of 1.250 M CH3CH2NH2, Kb=4.70×10^(-4),

with 0.520 M HCl.

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the half-way point of a titration

= the halfway point of a titration

= the half equivalence point of a titration

= the midpoint of a titration

= 적정에서 반-당량점

= 적정에서 반-중화점

[약염기-강산 적정에서 반-당량점]

반-당량점에서, [약염기] = [짝산] 이고,

pOH = pKb + log([짝산]/[약염기]) 이므로,

반-당량점에서, pOH = pKb

( 참고 https://ywpop.tistory.com/10228 )

pKb = –log(4.70×10^(-4))

= 3.33

= pOH

pH = 14.00 – 3.33

= 10.67

---> pH at the half-way point

답: pH = 10.7

[키워드] half-way point 151 mL 1.250 M CH3CH2NH2 0.520 M HCl