concentrations NaF and KCl each 0.10 M in the cell
Suppose that the concentrations of NaF and KCl
were each 0.10 M in the cell
Pb(s) | PbF2(s) | F^-(aq) || Cl^-(aq) | AgCl(s) | Ag(s)
Using the half-reactions
2AgCl(s) + 2e^- ⇌ 2Ag(s) + 2Cl^- and
PbF2(s) + 2e^- ⇌ Pb(s) + 2F^-,
calculate the cell voltage.
[참고] 표준 환원 전위
> AgCl + e^- → Ag + Cl^- ... E° = +0.222 V
> PbF2(s) + 2e^- ⇌ Pb(s) + 2F^- ... E° = –0.350 V
( 참고 https://ywpop.tistory.com/7027 )
2AgCl(s) + 2e^- ⇌ 2Ag(s) + 2Cl^-
Nernst 식
E = E° – (0.0592 V / n) × logQ
= E° – (0.0592 V / n) × log([생성물]/[반응물])
( 참고 https://ywpop.tistory.com/2900 )
= (+0.222) – (0.0592 / 2) × log((0.10)^2)
= +0.281 V
= E_red (환원전극)
PbF2(s) + 2e^- ⇌ Pb(s) + 2F^-
E = E° – (0.0592 V / n) × log([생성물]/[반응물])
= (–0.350) – (0.0592 / 2) × log((0.10)^2)
= –0.291 V
= E_ox (산화전극)
E_cell = E_red(환원전극) – E_red(산화전극)
= (환원된 물질의 환원전위) – (산화된 물질의 환원전위)
( 참고 https://ywpop.tistory.com/4558 )
= E_red – E_ox
= (+0.281) – (–0.291)
= +0.572 V
답: 0.572 V
[ 같은 글 https://ywpop.tistory.com/470631 ]
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