1.35 m solution of NaOCl in water mole fraction of NaOCl

A 1.35 m solution of NaOCl in water is prepared.

What is the mole fraction of the NaOCl?

1.35 m solution of NaOCl

= 1.35 mol NaOCl / 1 kg H2O

( 참고 https://ywpop.tistory.com/2667 )

H2O의 몰질량 = 18.015 g/mol 이므로,

1 kg H2O의 몰수를 계산하면,

n = W / M

( 참고 https://ywpop.tistory.com/7738 )

= 1000 g / (18.015 g/mol)

= 55.51 mol H2O

mole fraction of NaOCl

= 1.35 mol / (1.35 + 55.51 mol)

= 0.02374

답: 0.0237

[키워드] NaOCl 몰분율 기준