1.00 L N2 gas 25℃ 1.00 atm 2.00 g N2 -55℃

1.00 L N2 gas 25℃ 1.00 atm 2.00 g N2 -55℃

A 1.00 L flask contains nitrogen gas at 25℃ and 1.00 atm pressure. What is the final pressure in the flask if an additional 2.00 g of N2 gas is added to the flask and the flask cooled to –55℃?

PV = nRT 로부터,

( 참고 https://ywpop.blogspot.com/2024/05/ideal-gas-equation-pv-nrt.html )

처음 N2의 몰수를 계산하면,

n = PV / RT

= [(1.00) (1.00)] / [(0.08206) (273.15 + 25)]

= 0.04087 mol N2

2.00 g / (28 g/mol) = 0.07143 mol N2

( 참고 https://ywpop.tistory.com/7738 )

최종 압력을 계산하면,

P = nRT / V

= (0.04087 + 0.07143) (0.08206) (273.15 + (–55)) / (1.00)

= 2.01 atm

답: 2.01 atm

[키워드] pv nrt 기준