P4 248 g P4(s) + 5O2(g) → P4O10(s) ΔH -3013 kJ/mol

How much heat, in kJ, is evolved

when 248 g of white phosphorus (P4) burn in air?

P4(s) + 5O2(g) → P4O10(s) ... ΔH = –3013 kJ/mol

P의 원자량 = 31.0 g/mol 이므로,

P4의 몰질량 = 4 × (31.0 g/mol) = 124 g/mol

P4의 몰질량 = 123.8950 ≒ 124 g/mol 이므로,

248 g P4의 몰수를 계산하면,

248 g / (124 g/mol) = 2 mol P4

2 mol × (–3013 kJ/mol)

= –6026 kJ

답: –6026 kJ

[키워드] Calculate the heat evolved when 248 g of white phosphorus P4 burns in air according to equation