CuFeS2 SiO2 CuS Cu SO2(g) 85.36 g CuFeS2

CuFeS2 SiO2 CuS Cu SO2(g) 85.36 g CuFeS2



Copper exists in the form of CuFeS2 in copper ore.

Copper is isolated in a two-step process.

First, CuFeS2 is heated with SiO2 in the presence of oxygen

to form copper(I) sulfide, CuS:

2CuFeS2 + 2SiO2 + 4O2 → Cu2S + 2FeSiO3 + 3SO2

Cu2S is then heated with oxygen to form copper and SO2(g).

a) Write the balanced chemical equation for the second reaction.

b) Which atoms from which compounds are being oxidized,

and which atoms from which compounds are being reduced?

c) How many grams of copper would be isolated

from 85.36 g of CuFeS2 in copper ore?



a)

Cu2S + O2 → 2Cu + SO2



b)

redox Cu2S + O2 → 2Cu + SO2

( 참고 https://ywpop.tistory.com/7339 )


Cu2S → Cu

> Cu의 산화수는 +1에서 0으로 감소, 환원됨.


Cu2S → SO2

> S의 산화수는 –2에서 +4로 증가, 산화됨.


O2 → SO2

> O의 산화수는 0에서 –2로 감소, 환원됨.



c)

2CuFeS2 + 2SiO2 + 4O2 → Cu2S + 2FeSiO3 + 3SO2

CuFeS2 : Cu2S = 2 : 1 계수비(= 몰수비) 이고,


Cu2S + O2 → 2Cu + SO2

Cu2S : Cu = 1 : 2 계수비(= 몰수비) 이므로,


CuFeS2 : Cu = 1 : 1 계수비(= 몰수비).

---> CuFeS2의 몰수만큼, Cu를 얻을 수 있다.



CuFeS2의 몰질량 = 183.52 g/mol 이고,

Cu의 몰질량 = 63.55 g/mol 이므로,

(85.36 g) (1 mol / 183.52 g) (63.55 g / 1 mol)

= (85.36) (1 / 183.52) (63.55)

= 29.56 g Cu




[키워드] CuFeS2 기준, 구리 광석 기준



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