ClF(g) 0.88 D 1.63 Å Cl F charge

ClF(g) 0.88 D 1.63 Å Cl F charge

dipole moments of diatomic molecules

The dipole moment of chlorine monofluoride, ClF(g), is 0.88 D.

The bond length of the molecule is 1.63 Å.

a) Which atom is expected to have the partial negative charge?

b) What is the charge on that atom in units of e?

where 1 D = 3.34×10^(-30) C•m

where 1 e = 1.60×10^(-19) C

where 1 Å = 10^(-10) m

a) Which atom is expected to have the partial negative charge?

답: F

( 참고: 전기음성도 https://ywpop.tistory.com/2567 )

b) What is the charge on that atom in units of e?

μ = Q × r

( 참고 https://ywpop.tistory.com/2581 )

Q = μ / r

= [(0.88 D) (3.34×10^(-30) C•m / 1 D)]

/ [(1.63 Å) (1 m / 10^10 Å)]

= [(0.88) (3.34×10^(-30))] / [(1.63) (1 / 10^10)]

= 1.8032×10^(-20) C

1.8032×10^(-20) C × [1 e / (1.60×10^(-19) C)]

= 0.1127 e

답: 0.11 e

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