0.225 M Na2SO4 15.0 mL + BaCl2 19.4 mL

0.225 M Na2SO4 15.0 mL + BaCl2 19.4 mL

What is the molarity of a BaCl2 solution

if 19.4 mL of the BaCl2 solution is needed to react with

15.0 mL of a 0.225 M Na2SO4 solution?

[참고] 0.216 M BaCl2 26.8 mL + 0.330 M Na2SO4

[ https://ywpop.blogspot.com/2024/05/0216-m-bacl2-268-ml-0330-m-na2so4.html ]

Na2SO4(aq) + BaCl2(aq) → BaSO4(s) + 2NaCl(aq)

Na2SO4 : BaCl2 = 1 : 1 계수비(= 몰수비) 이므로,

MV = M’V’ = mol

(0.225 M) (15.0 mL) = (? M) (19.4 mL)

? = (0.225) (15.0) / (19.4)

= 0.174 M

답: 0.174 M

[키워드] mv 화학량론 기준, 화학량론 mv 기준, Na2SO4 + BaCl2 반응 기준, BaCl2 + Na2SO4 반응 기준