HNO3 25.0 mL 0.115 M Ba(OH)2 28.15 mL

If 28.15 mL of 0.115 M barium hydroxide

is required to neutralize 25.0 mL of nitric acid,

what is the molarity of the acid?

2HNO3 + Ba(OH)2 → Ba(NO3)2 + 2H2O

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aMV = bM’V’

H^+의 몰수 = OH^-의 몰수

( 참고 https://ywpop.tistory.com/4689 )

(1) (? M) (25.0 mL) = (2) (0.115 M) (28.15 mL)

? = [(2) (0.115) (28.15)] / [(1) (25.0)]

= 0.259 M

답: 0.259 M

[키워드] HNO3 + Ba(OH)2 중화 기준