fcc lattice edge 408 pm density 10.49 g/cm3 mass

An element crystallizes in a face-centered cubic lattice.

If the edge length of the unit cell is 408 pm

and the density is 10.49 g/cm^3,

calculate the atomic mass of the element.

An element crystallizes in a face-centered cubic lattice.

The edge of the unit cell is 4.089×10^(-8) cm,

and the density of the crystal is 10.49 g/cm^3.

Calculate the atomic weight of the element.

Identify the element.

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fcc의 z = 4 atoms

( 참고 https://ywpop.tistory.com/12440 )

(408 pm) × (1×10^(-10) cm / 1 pm)

= (408) × (1×10^(-10))

= 4.08×10^(-8) cm

M = [ρ × N_A × a^3] / z

( 참고 https://ywpop.tistory.com/12439 )

= [10.49 × (6.022×10^23) × (4.08×10^(-8))^3] / 4

= 107.26 g/mol

---> silver, Ag

[참고] bcc lattice edge 0.408 pm density 10.49 g/cm3 mass

bcc의 z = 2 atoms

(0.408 pm) × (1×10^(-10) cm / 1 pm)

= (0.408) × (1×10^(-10))

= 4.08×10^(-11) cm

M = [ρ × N_A × a^3] / z

= [10.49 × (6.022×10^23) × (4.08×10^(-11))^3] / 2

= 2.145×10^(-7) g/mol

---> 원자량이 이렇게 나올 수는 없다.

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