ethane 1 mol% gas 20℃ 20 atm water

A gas with 1% mol of ethane

is in contact with water at 20℃ and 20 atm.

What is the mol fraction of dissolved ethane?

A gas containing 1.00 mole percent of ethane

is in contact with water at 20℃ and 20 atm.

Estimate the mole fraction of dissolved ethane.

Given that the Henry’s law constant for ethane

in water at 20℃ is 2.64×10^4 atm/mole fraction.

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From 돌턴의 분압 법칙,

P_eth = P_tot × X_eth

( 참고 https://ywpop.tistory.com/48 )

= 20 atm × (1.00/100)

= 0.2 atm

---> ethane의 분압

From 헨리의 법칙,

P_eth = k_H × C_eth

( 참고 https://ywpop.tistory.com/1911 )

C_eth = P_eth / k_H

= 0.2 atm / (2.64×10^4 atm/mole fraction)

= 7.6×10^(-6)

---> 수용액 속 ethane의 몰분율

답: 7.6×10^(-6)

[키워드] 돌턴과 헨리 기준, 헨리와 돌턴 기준, 기체의 몰분율과 액체의 몰분율 기준, 액체의 몰분율과 기체의 몰분율 기준