1000 K 2NO(g) + Br2(g) ⇌ 2NOBr(g) Kc 1.3×10^(-2)
4NOBr(g) ⇌ 4NO(g) + 2Br2(g)
The equilibrium constant for the reaction
2NO(g) + Br2(g) ⇌ 2NOBr(g)
is Kc = 1.3×10^(-2) at 1000 K.
Calculate Kc for
4NOBr(g) ⇌ 4NO(g) + 2Br2(g)
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[참고] 이론적 평형상수 계산
[ https://ywpop.tistory.com/4154 ]
2NO(g) + Br2(g) ⇌ 2NOBr(g)
---> 4NOBr(g) ⇌ 4NO(g) + 2Br2(g)
역반응 & ×2 했으므로,
① 역반응
Kc = 1 / (1.3×10^(-2))
= 76.9
② ×2
Kc = 1 / (1.3×10^(-2))^2
= 5917
또는
Kc = (1.3×10^(-2))^(-2)
= 5917
답: Kc = 5917
[키워드] 이론적 평형상수 기준
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