E° for the reaction. Cu^+ + e^- → Cu

Given:

(1) Cu^2+ + 2e^- → Cu, E° = 0.337 V

(2) Cu^2+ + e^- → Cu^+, E° = 0.153 V

Electrode potential, E° for the reaction,

Cu^+ + e^- → Cu, will be

(a) 0.90 V

(b) 0.30 V

(d) 0.52 V

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ΔG = –nFE

( 참고 https://ywpop.tistory.com/10066 )

.. Cu^2+ + 2e^- → Cu ... ΔG1

+) Cu^+ → Cu^2+ + e^- ... –ΔG2

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.. Cu^+ + e^- → Cu ... ΔG3

ΔG3 = ΔG1 + (–ΔG2) = ΔG1 – ΔG2

–n3•F•E3 = (–n1•F•E1) – (–n2•F•E2)

F를 소거하면,

–n3•E3 = (–n1•E1) – (–n2•E2)

n3 = 1 이므로,

E3 = –[(–n1•E1) – (–n2•E2)]

= n1•E1 – n2•E2

= ((2) (0.337 V)) – ((1) (0.153 V))

= 0.521

답: (d) 0.52 V

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