2A → B second order 24℃ 51 /M•min [A]_0 = 0.0092 M

2A → B second order 24℃ 51 /M•min [A]_0 = 0.0092 M

The reaction 2A → B is second order

with a rate constant of 51 /M•min at 24℃.

a) Starting with [A]_0 = 0.0092 M,

how long will it take for [A]_t = 3.7×10^(-3) M?

b) Calculate the half-life of the reaction.

반응 2A → B는 이차 반응이고

24℃에서 속도 상수가 51 /M•분이다.

a) [A]_0 = 0.0092 M로 시작하여

[A]_t = 3.7×10^(-3) M이 되기까지

시간이 얼마나 걸리겠는가?

b) 이 반응의 반감기를 계산하라.

2차 반응 속도식

(1 / C_t) = k•t + (1 / C_0)

( 참고 https://ywpop.tistory.com/25 )

k•t = (1 / C_t) – (1 / C_0)

t = [(1 / C_t) – (1 / C_0)] / k

= [(1 / (3.7×10^(-3))) – (1 / 0.0092)] / 51

= 3.168 min

t_1/2 = 1 / (k [A]_0)

= 1 / (51 × 0.0092)

= 2.131 min

[키워드] 2차 반응 기준

Reaction 2A → B is a second-order reaction and has a rate constant of 51 /M·min at 24°C. a) Starting with [A]_0 = 0.0092 M, how long will it take to reach [A]_t = 3.7×10^(-3) M? b) Calculate the half-life of this reaction.