1.252 g cyclohexanol C6H12O 27.00℃ to 31.11℃ 11.3 kJ/℃

1.252 g cyclohexanol C6H12O 27.00℃ to 31.11℃ 11.3 kJ/℃

A 1.252 g sample of cyclohexanol (C6H12O) was burned in a constant-volume bomb calorimeter where the temperature of the water increased from 27.00℃ to 31.11℃. If the heat capacity of the bomb plus water is 11.3 kJ/℃, what is the molar heat of combustion of cyclohexanol?

열용량의 정의로부터,

q = C Δt

( 참고 https://ywpop.tistory.com/2897 )

= (11.3 kJ/℃) (31.11 – 27.00 ℃)

= 46.443 kJ

---> bomb plus water가 흡수한 열

---> 연소열 = –46.443 kJ

cyclohexanol, C6H12O의 몰질량 = 100.16 g/mol 이므로,

n = W / M

( 참고 https://ywpop.tistory.com/7738 )

= 1.252 g / (100.16 g/mol)

= 0.0125 mol cyclohexanol

몰당 연소열을 계산하면,

–46.443 kJ / 0.0125 mol

= –3715.44 kJ/mol

답: ΔH = –3720 kJ/mol

[키워드] 1.252 g 사이클로헥산올의 연소열 기준, 1.252 g 시클로헥산올의 연소열 기준, 1.252 g cyclohexanol의 연소열 기준