15.0 mL 0.149 M NaOH 25.2 mL 15.0 mL 0.122 M KMnO4

15.0 mL 0.149 M NaOH 25.2 mL 15.0 mL 0.122 M KMnO4

A 15.0 mL sample of an oxalic acid solution requires

25.2 mL of 0.149 M NaOH for neutralization.

Calculate the volume of a 0.122 M KMnO4 solution needed to react

with a second 15.0 mL sample of the oxalic acid solution.

(Hint: Oxalic acid is a diprotic acid.)

옥살산 + NaOH 반응식

H2C2O4(aq) + 2NaOH(aq) → Na2C2O4(aq) + 2H2O(l)

( 참고 https://ywpop.tistory.com/5393 )

aMV = bM’V’

( 참고 https://ywpop.tistory.com/4689 )

(2) (? M) (15.0 mL) = (1) (0.149 M) (25.2 mL)

? = [(1) (0.149) (25.2)] / [(2) (15.0)] = 0.125 M

---> 옥살산의 몰농도

옥살산 + KMnO4 반응식

5H2C2O4 + 2KMnO4 + 3H2SO4 → K2SO4 + 2MnSO4 + 10CO2 + 8H2O

( 참고 https://ywpop.tistory.com/5391 )

또는

5C2O4^2- + 2MnO4^- + 16H^+ → 10CO2 + 2Mn^2+ + 8H2O

( 참고 https://ywpop.tistory.com/6357 )

aMV = bM’V’

(2) (0.125 M) (15.0 mL) = (5) (0.122 M) (? mL)

? = [(2) (0.125) (15.0)] / [(5) (0.122)] = 6.1475 mL

답: 6.15 mL

[키워드] H2C2O4 + NaOH 반응 기준, H2C2O4 + KMnO4 반응 기준, NaOH + H2C2O4 반응 기준, KMnO4 + H2C2O4 반응 기준, 옥살산 + NaOH 반응 기준, 옥살산 + KMnO4 반응 기준, NaOH + 옥살산 반응 기준, KMnO4 + 옥살산 반응 기준