6.90 g solid 48.8 g acetic acid boil 119.3℃ mol mass

6.90 g solid 48.8 g acetic acid boil 119.3℃ mol mass

A 6.90 g sample of a nonvolatile nonelectrolyte blue crystalline solid is dissolved in 48.8 g of acetic acid, producing a solution that bolis at 119.3℃. Find the molar mass of the blue solid in g/mol.

---------------------------------------------------

끓는점오름. Boiling-point elevation

ΔTb = Kb × m

( 참고 https://ywpop.tistory.com/1920 )

m = ΔTb / Kb

= (119.3 – 117.90) / 3.07

= 0.456026 m

몰랄농도 = 용질 mol수 / 용매 kg수

( 참고 https://ywpop.tistory.com/2667 )

용질 mol수 = 몰랄농도 × 용매 kg수

= (0.456026 mol/kg) × (48.8/1000 kg)

= 0.022254 mol

몰질량 = 6.90 g / 0.022254 mol

= 310.06 g/mol

( 참고 https://ywpop.tistory.com/7738 )

답: 310.06 g/mol

[키워드] 끓는점오름 기준, acetic acid의 Kb 기준, 아세트산의 Kb 기준, 7.80 g solid 41.0 g acetic acid boil 119.7℃ mol mass, 5.90 g solid 20.9 g acetic acid boil 120.5℃ mol mass