6.75 g SO2Cl2 2.00 L 648 K 0.0345 mol SO2 Kc

A quantity of 6.75 g of SO2Cl2

was placed in a 2.00-L flask.

At 648 K, there is 0.0345 mole of SO2 present.

Calculate Kc for the reaction

SO2Cl2(g) ⇌ SO2(g) + Cl2(g)

---------------------------------------------------

SO2Cl2의 몰질량 = 134.97 g/mol 이므로,

6.75 g / (134.97 g/mol) = 0.0500 mol SO2Cl2

[SO2Cl2] = 0.0500 mol / 2.00 L

= 0.0250 M

[그림] A ⇌ B + C 반응의 ICE table과 평형 상수식.

Kc = [SO2] [Cl2] / [SO2Cl2]

= (x) (x) / (0.0250 – x)

평형에서,

[SO2] = 0.0345 mol / 2.00 L

= 0.01725 M = x

Kc = 0.01725^2 / (0.0250 – 0.01725)

= 0.038395

답: 0.0384

[ 관련 예제 https://ywpop.tistory.com/17511 ]

25℃ SO2Cl2 SO2(g) Cl2(g) 12.5% 0.900 atm Kp

[키워드] SO2Cl2(g) ⇌ SO2(g) + Cl2(g) 기준, SO2Cl2 ⇌ SO2 + Cl2 기준