어떤 원소 1.40% 203.973 amu 24.10% 205.9745 amu

An element consists of

1.40% of an isotope with mass 203.973 amu,

24.10% of an isotope with mass 205.9745 amu,

22.10% of an isotope with mass 206.9759 amu, and

52.40% of an isotope with mass 207.9766 amu.

Calculate the average atomic mass and identify the element.

a. 200.6 amu, Hg

b. 209.0 amu, Bi

c. 207.2 amu, Pb

d. None of the above is correct.

---------------------------------------------------

원자량 = 동위원소의 평균 원자량

= Σ [ (동위원소의 질량) × (동위원소의 존재비) ]

( 참고 https://ywpop.tistory.com/3085 )

(1.40/100)×203.973

+ (24.10/100)×205.9745

+ (22.10/100)×206.9759

+ (52.40/100)×207.9766

= 207.2169

답: c. 207.2 amu, Pb. 납(lead)

[키워드] 납의 동위원소 기준문서, 납의 평균 원자량 기준문서, Pb의 동위원소 기준문서, Pb의 평균 원자량 기준문서, 1.40% 203.973 amu 24.10% 205.9745 amu 22.10% 206.9759 amu 52.40% 207.9766 amu