0.002 M HNO3 [H^+] [OH^-] pH pOH

What are the [H^+], [OH^-], pH and pOH

of a 0.002 M solution of HNO3?

HNO3는 강산이므로,

[HNO3] = [H^+] = 0.002 M

( 참고 https://ywpop.tistory.com/17072 )

Kw = [H^+] [OH^-] = 1.0×10^(-14)

( 참고 https://ywpop.tistory.com/2706 )

[OH^-] = (1.0×10^(-14)) / 0.002

= 5×10^(-12) M

pH = –log[H^+]

= –log(0.002) = 2.7

pOH = 14 – pH = 11.3

[키워드] HNO3 용액의 pH 기준