uncertainty position electron velocity 417 km/s
Find the uncertainty in position (in nm)
associated with an electron
that is moving with a velocity of 417 km/s.
The uncertainty in the velocity is 5.00%.
The electron rest mass is 9.11×10^(-31) kg.
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[참고] 하이젠베르크의 불확정성 원리
Heisenberg’s uncertainty principle
[ https://ywpop.tistory.com/7186 ]
Δv = (417 km/s) (1000 m / 1 km) (5.00/100)
= (417) (1000) (5.00/100)
= 20850 m/s
(Δx) × (ΔP) ≧ (h / 4π)
> h = 6.626×10^(-34) kg•m^2/s
Δx = h / (m × Δv × 4π)
= (6.626×10^(-34)) / ((9.11×10^(-31)) × 20850 × 4π)
= 2.78×10^(-9) m
(2.78×10^(-9) m) (10^9 nm / 1 m) = 2.78 nm
답: 2.78 nm
[참고] Δx를 한 번에 계산하면,
(6.626×10^(-34)) / ((9.11×10^(-31)) × 417000×(5.00/100) × 4π)
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